Topics differ from semester to semester, so there might be some questions you aren't able to answer.
One final.
Another.
Wednesday, December 8, 2010
Monday, December 6, 2010
last time: redim
resize an array
using a for each loop
For Each letter in sentence.ToCharArray()
If (letter >= "A") And (letter <= "Z") Then
index = Asc(letter) - 65 'The ANSI value of "A"is 65
charCount(index) += 1
End If
Next
how freq table might be useful
huffman trees
http://en.wikipedia.org/wiki/Huffman_coding
AN example of using freq tables
"If arrayOne() and arrayTwo() have been declared with the same data type, then the statement
arrayOne = arrayTwo
makes arrayOne() an exact duplicate of arrayTwo(). It will have the same size and contain the same information.
"
This comment is false. fixed in later versions of the book
so, how DO we copy an array?
two ways:
1)
Dim a(4) As Integer = {6, 8, 2, -8, 0}
Dim b() as Integer
' i want to make b an exact duplicate of a
ReDim b(UBound(a))
For I = 0 to UBound(a)
b(i) = a(i)
Next
2)
b = a.Clone()
HW: arrays, creating and accessing
q 28, 32
resize an array
using a for each loop
For Each letter in sentence.ToCharArray()
If (letter >= "A") And (letter <= "Z") Then
index = Asc(letter) - 65 'The ANSI value of "A"is 65
charCount(index) += 1
End If
Next
how freq table might be useful
huffman trees
http://en.wikipedia.org/wiki/Huffman_coding
AN example of using freq tables
"If arrayOne() and arrayTwo() have been declared with the same data type, then the statement
arrayOne = arrayTwo
makes arrayOne() an exact duplicate of arrayTwo(). It will have the same size and contain the same information.
"
This comment is false. fixed in later versions of the book
so, how DO we copy an array?
two ways:
1)
Dim a(4) As Integer = {6, 8, 2, -8, 0}
Dim b() as Integer
' i want to make b an exact duplicate of a
ReDim b(UBound(a))
For I = 0 to UBound(a)
b(i) = a(i)
Next
2)
b = a.Clone()
HW: arrays, creating and accessing
q 28, 32
Wednesday, December 1, 2010
Array
a collection
the "problem" with dealing with a collection as a bunch of separate variables.
1) unweildy
2) not easily changable to diff number of variable
Dim score(29) As Double
Dim student(29) As String
score(0) = 87
score(1) = 92
If you write programs involving large arrays
a good idea is to test using small arrays first
For i As Integer = 0 To 29
lstBox.Items.Add(score(i))
Next
a new loop!
For Each x in score
lstBox.Items.Add(x)
Next
we can make the array a class-level variable
and fill it in the Form_Load event
Dim teamName(3) As String = {"Packers", "Packers", "Jets", "Chiefs"}
often, we will use loops to iterate thru an array.
easier way: use for each loop
harder way: for i = 0 to whatever the upper bound is
problem: 29 is a "magic number". makes code hard to read. introduces errors. let us say i change to 60 students!
for i = 0 to UBound(scores)
scores(i) = 90
next
for i = 0 to scores.GetUpperBound(0)
scores(i) = 90
next
Dim scores() As Double
realize that scores, or any array, is a reference type
ReDim scores(29)
ReDim scores(n)
dynamic memory allocation
Dim scores(3) As Integer
scores(0) = 58
scores(1) = 78
scores(2) = 100
scores(3) = 98
ReDim scores(4)
' alternatively
ReDim Preserve scores(4)
will preserve the values
a collection
the "problem" with dealing with a collection as a bunch of separate variables.
1) unweildy
2) not easily changable to diff number of variable
Dim score(29) As Double
Dim student(29) As String
score(0) = 87
score(1) = 92
If you write programs involving large arrays
a good idea is to test using small arrays first
For i As Integer = 0 To 29
lstBox.Items.Add(score(i))
Next
a new loop!
For Each x in score
lstBox.Items.Add(x)
Next
we can make the array a class-level variable
and fill it in the Form_Load event
Dim teamName(3) As String = {"Packers", "Packers", "Jets", "Chiefs"}
often, we will use loops to iterate thru an array.
easier way: use for each loop
harder way: for i = 0 to whatever the upper bound is
problem: 29 is a "magic number". makes code hard to read. introduces errors. let us say i change to 60 students!
for i = 0 to UBound(scores)
scores(i) = 90
next
for i = 0 to scores.GetUpperBound(0)
scores(i) = 90
next
Dim scores() As Double
realize that scores, or any array, is a reference type
ReDim scores(29)
ReDim scores(n)
dynamic memory allocation
Dim scores(3) As Integer
scores(0) = 58
scores(1) = 78
scores(2) = 100
scores(3) = 98
ReDim scores(4)
' alternatively
ReDim Preserve scores(4)
will preserve the values
Monday, November 29, 2010
lecture notes
For Loops
are an example of syntactic sugar
1) how do i start?
2) how do i end?
3) step
For i = 1 to 10
ListBox1.Items.Add(i*i)
Next
When should I use a For loop?
1) you want to do something a fixed number of times
(In this instance, i don't *use* the variable i inside the loop at all)
2) when you want to generate a series of numbers
ex 1:
Dim year as Integer
pop = 300000
For year = 2006 To 2010
LstTable.Items.Add(year & " " & pop)
pop = pop + pop * 0.03
Next
Alternatively:
pop = 300000
For year as integer = 2006 To 2010
LstTable.Items.Add(year & " " & pop)
pop = pop + pop * 0.03
Next
if I have:
x operator= 6
x = x operator 6
for loops, 30-40 even
row = ""
for i = 1 to 10
row = row & "*"
next
for i = 1 to 10
listbox1.items.add(row)
next
for i = 1 to 10
row = ""
for i = 1 to 10
row = row & "*"
next
listbox1.items.add(row)
next
are an example of syntactic sugar
1) how do i start?
2) how do i end?
3) step
For i = 1 to 10
ListBox1.Items.Add(i*i)
Next
When should I use a For loop?
1) you want to do something a fixed number of times
(In this instance, i don't *use* the variable i inside the loop at all)
2) when you want to generate a series of numbers
ex 1:
Dim year as Integer
pop = 300000
For year = 2006 To 2010
LstTable.Items.Add(year & " " & pop)
pop = pop + pop * 0.03
Next
Alternatively:
pop = 300000
For year as integer = 2006 To 2010
LstTable.Items.Add(year & " " & pop)
pop = pop + pop * 0.03
Next
if I have:
x operator= 6
x = x operator 6
for loops, 30-40 even
row = ""
for i = 1 to 10
row = row & "*"
next
for i = 1 to 10
listbox1.items.add(row)
next
for i = 1 to 10
row = ""
for i = 1 to 10
row = row & "*"
next
listbox1.items.add(row)
next
Wednesday, November 24, 2010
lecture notes
Nesting: putting one loop in another
Loop thru values of X in (0 thru 2)
Loop thru values of y in (0 thru 3)
Print (x, y)
End Loop
End Loop
LISTS.TXT
' the names of other phonebook files
CLIENTS.TXT
FRIENDS.TXT
KINFOLK.TXT
Loop thru filenames in the LISTS.TXT file
Open the current filename
Loop thru the entries in the current file
see if name occurs in current file
End Loop
End Loop
Private Sub btnDisplay_Click(...) Handles btnDisplay.Click
Dim foundFlag As Boolean
Dim fileName As String
Dim name As String = ""
Dim phoneNum As String = ""
Dim sr1 As IO.StreamReader = IO.File.OpenText ("LISTS.TXT")
txtNumber.Text = "Name not found."
' by the way, i use a goto to break out multiple
' levels when we find the actual word
Do While sr1.Peek <> -1
fileName = sr1.ReadLine
Dim sr2 As IO.StreamReader = IO.File.OpenText(fileName)
Do While sr2.Peek <> -1
name = sr2.ReadLine
phoneNum = sr2.ReadLine
If name = txtName.Text Then
txtNumber.Text = name & " " & phoneNum
Goto Here
Endif
Loop
Loop
sr1.Close()
Here:
End Sub
HW:
Processing Lists of Data with Do Loops
question 20-24, even
Write a program to find and display the largest of a collection of positive numbers contained in a text file. (Test the program with the collection of numbers 89, 77, 95, and 86.)
Dim max as Integer
max = 0
Do While sr.Peek <> -1
current = sr.ReadLine
' is my optimistic assumption wrong?
If current > max Then
max = current
EndIf
Loop
Debug.Print("The max value is: " & max)
Loop thru values of X in (0 thru 2)
Loop thru values of y in (0 thru 3)
Print (x, y)
End Loop
End Loop
LISTS.TXT
' the names of other phonebook files
CLIENTS.TXT
FRIENDS.TXT
KINFOLK.TXT
Loop thru filenames in the LISTS.TXT file
Open the current filename
Loop thru the entries in the current file
see if name occurs in current file
End Loop
End Loop
Private Sub btnDisplay_Click(...) Handles btnDisplay.Click
Dim foundFlag As Boolean
Dim fileName As String
Dim name As String = ""
Dim phoneNum As String = ""
Dim sr1 As IO.StreamReader = IO.File.OpenText ("LISTS.TXT")
txtNumber.Text = "Name not found."
' by the way, i use a goto to break out multiple
' levels when we find the actual word
Do While sr1.Peek <> -1
fileName = sr1.ReadLine
Dim sr2 As IO.StreamReader = IO.File.OpenText(fileName)
Do While sr2.Peek <> -1
name = sr2.ReadLine
phoneNum = sr2.ReadLine
If name = txtName.Text Then
txtNumber.Text = name & " " & phoneNum
Goto Here
Endif
Loop
Loop
sr1.Close()
Here:
End Sub
HW:
Processing Lists of Data with Do Loops
question 20-24, even
Write a program to find and display the largest of a collection of positive numbers contained in a text file. (Test the program with the collection of numbers 89, 77, 95, and 86.)
Dim max as Integer
max = 0
Do While sr.Peek <> -1
current = sr.ReadLine
' is my optimistic assumption wrong?
If current > max Then
max = current
EndIf
Loop
Debug.Print("The max value is: " & max)
Monday, November 22, 2010
lecture
Write a function that returns n factorial
txtBox1.Text = fact(5)
1) where do i start?
2) where do i end?
3) how do i get to the next step?
Function fact(byval n as integer) As integer
dim i as integer
dim prod as integer
i = 1
prod = 1
Do
prod = prod * i
i += 1
Loop Until i = n + 1
Return prod
End Function
prod is a accumulator
off by one error
we calculated factorial using "iteration"
"iteration" is a fancy name for loops
write me a function which is the SUM of the nums from 1 to n:
Function sum(byval n as integer) As integer
dim i as integer
dim total as integer
i = 1
total = 0
Do
total = total + i
i += 1
Loop Until i > n
Return total
End Function
sr.Peek will return -1 if reached EOF (end of file)
lets say i want to read firstname, lastname, and print it out.
1) where do i start?
2) where do i end?
3) how do i get to the next step?
Dim sr As IO.StreamReader
sr = IO.File.OpenText("c:\josh\Names.txt")
Dim firstname, lastname as String
Do While sr.Peek <> -1
firstname = sr.ReadLine
lastname = sr.ReadLine
ListBox1.Items.Add("first: " & firstname, & vbTab & "last" & lastname)
Loop
Private Sub btnDisplay_Click(...) Handles btnDisplay.Click
Dim name, phoneNum As String
Dim sr As IO.StreamReader = IO.File.OpenText("PHONE.TXT")
' pessimistic assumption
txtNumber.Text = "Name not found."
Do While sr.Peek <> -1
name = sr.ReadLine
phoneNum = sr.ReadLine
If name = txtName.Text Then
' my pessimistic assumption was proven false
txtNumber.Text = name & " " & phoneNum
' make things faster; this is optional
Exit Do
EndIf
Loop
sr.Close()
End Sub
txtBox1.Text = fact(5)
1) where do i start?
2) where do i end?
3) how do i get to the next step?
Function fact(byval n as integer) As integer
dim i as integer
dim prod as integer
i = 1
prod = 1
Do
prod = prod * i
i += 1
Loop Until i = n + 1
Return prod
End Function
prod is a accumulator
off by one error
we calculated factorial using "iteration"
"iteration" is a fancy name for loops
write me a function which is the SUM of the nums from 1 to n:
Function sum(byval n as integer) As integer
dim i as integer
dim total as integer
i = 1
total = 0
Do
total = total + i
i += 1
Loop Until i > n
Return total
End Function
sr.Peek will return -1 if reached EOF (end of file)
lets say i want to read firstname, lastname, and print it out.
1) where do i start?
2) where do i end?
3) how do i get to the next step?
Dim sr As IO.StreamReader
sr = IO.File.OpenText("c:\josh\Names.txt")
Dim firstname, lastname as String
Do While sr.Peek <> -1
firstname = sr.ReadLine
lastname = sr.ReadLine
ListBox1.Items.Add("first: " & firstname, & vbTab & "last" & lastname)
Loop
Private Sub btnDisplay_Click(...) Handles btnDisplay.Click
Dim name, phoneNum As String
Dim sr As IO.StreamReader = IO.File.OpenText("PHONE.TXT")
' pessimistic assumption
txtNumber.Text = "Name not found."
Do While sr.Peek <> -1
name = sr.ReadLine
phoneNum = sr.ReadLine
If name = txtName.Text Then
' my pessimistic assumption was proven false
txtNumber.Text = name & " " & phoneNum
' make things faster; this is optional
Exit Do
EndIf
Loop
sr.Close()
End Sub
Wednesday, November 17, 2010
lecture notes
q 23
c = -40
f = (9/5)*c + 32
ListBox1.Items.Add("c:" & c & vbTab & "f:" & f)
the actual code:
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
c = -40
Do
f = (9 / 5) * c + 32
ListBox1.Items.Add("c:" & c & vbTab & "f:" & f)
c += 5
Loop Until c > 40
End Sub
End Class
q 25:
1) where do we start (initialization)?
2) where do we end? (terminating condition)
3) how do we get there? each step (increment)
'Dim pop as Double
'pop = 6.5
Dim pop as Long
pop = 6.5 * 10 ^ 9
Const percent = 1.2 / 100
Dim year as Integer = 2006
Do
ListBox1.Items.Add("year:" & year & vbTab & "pop:" & pop)
year += 1
pop = pop + pop * percent
Loop Until pop >= 10 * 10^9
ListBox1.Items.Add("year:" & year & vbTab & "pop:" & pop)
Different roles for variables when it comes to loops
1) loop control variable
2) counter
3) accumulator
4) flag
q 27:
Write a program to display all the numbers between 1 and 100 that are part of the Fibonacci sequence. The Fibonacci sequence begins 1, 1, 2, 3, 5, 8,..., where each new number in the sequence is found by adding the previous two numbers in the sequence.
prev = 1
cur = 1
Do
ListBox1.Items.Add("num:" & vbTab & cur)
temp = prev
prev = cur
cur = temp + cur
Loop Until cur > 100
' now, using mathematic notation
Fn = 1
Fn_1 = 0
Do
ListBox1.Items.Add("num:" & vbTab & Fn)
Fn_2 = Fn_1
Fn_1 = Fn
Fn = Fn_1 + Fn_2
Loop Until Fn > 100
using iteration to calculate Fibonacci
HW: Do Loops, q 24-36, evens
c = -40
f = (9/5)*c + 32
ListBox1.Items.Add("c:" & c & vbTab & "f:" & f)
the actual code:
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
c = -40
Do
f = (9 / 5) * c + 32
ListBox1.Items.Add("c:" & c & vbTab & "f:" & f)
c += 5
Loop Until c > 40
End Sub
End Class
q 25:
1) where do we start (initialization)?
2) where do we end? (terminating condition)
3) how do we get there? each step (increment)
'Dim pop as Double
'pop = 6.5
Dim pop as Long
pop = 6.5 * 10 ^ 9
Const percent = 1.2 / 100
Dim year as Integer = 2006
Do
ListBox1.Items.Add("year:" & year & vbTab & "pop:" & pop)
year += 1
pop = pop + pop * percent
Loop Until pop >= 10 * 10^9
ListBox1.Items.Add("year:" & year & vbTab & "pop:" & pop)
Different roles for variables when it comes to loops
1) loop control variable
2) counter
3) accumulator
4) flag
q 27:
Write a program to display all the numbers between 1 and 100 that are part of the Fibonacci sequence. The Fibonacci sequence begins 1, 1, 2, 3, 5, 8,..., where each new number in the sequence is found by adding the previous two numbers in the sequence.
prev = 1
cur = 1
Do
ListBox1.Items.Add("num:" & vbTab & cur)
temp = prev
prev = cur
cur = temp + cur
Loop Until cur > 100
' now, using mathematic notation
Fn = 1
Fn_1 = 0
Do
ListBox1.Items.Add("num:" & vbTab & Fn)
Fn_2 = Fn_1
Fn_1 = Fn
Fn = Fn_1 + Fn_2
Loop Until Fn > 100
using iteration to calculate Fibonacci
HW: Do Loops, q 24-36, evens
Subscribe to:
Posts (Atom)